-6.6x^2+17x+140=0

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Solution for -6.6x^2+17x+140=0 equation:



-6.6x^2+17x+140=0
a = -6.6; b = 17; c = +140;
Δ = b2-4ac
Δ = 172-4·(-6.6)·140
Δ = 3985
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{3985}}{2*-6.6}=\frac{-17-\sqrt{3985}}{-13.2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{3985}}{2*-6.6}=\frac{-17+\sqrt{3985}}{-13.2} $

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